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9v^2-55v=0
a = 9; b = -55; c = 0;
Δ = b2-4ac
Δ = -552-4·9·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-55}{2*9}=\frac{0}{18} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+55}{2*9}=\frac{110}{18} =6+1/9 $
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